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=36-16G^2
We move all terms to the left:
-(36-16G^2)=0
We get rid of parentheses
16G^2-36=0
a = 16; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·16·(-36)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$G_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*16}=\frac{-48}{32} =-1+1/2 $$G_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*16}=\frac{48}{32} =1+1/2 $
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